Guide

How these diagrams are drawn

The same sign convention and equilibrium steps used in MMD written papers. Worked into every problem in this studio.

Sign convention

  • Shear force at a cut is the vertical resultant of all forces to the left. Upward on the left is positive.
  • Bending moment is positive when the beam sags (hogging is negative). This is the marine / Capt. Subramaniam convention.
  • Point loads and UDLs are drawn downward. Knife-edge reactions are drawn upward unless the support is holding the beam down.

Finding reactions

  1. Replace self-weight with a UDL w = W / L, or a single load W at the centroid if you only need reactions.
  2. ΣV = 0 gives RA + RB = total downward load.
  3. ΣM about one support gives the other reaction. Check by summing moments about the second support.
  4. A beam on a rigid flat bed has no concentrated reactions. The bed pushes up at total load / length, uniformly.
  5. A cantilever wall supplies both a vertical force and a fixing moment.

Walking the beam

SF jumps by a concentrated force (up for a reaction, down for a load). Under a UDL, SF changes linearly. BM is the running integral of SF, so a linear SF makes a parabolic BM. Maximum sagging or hogging BM occurs where SF crosses zero, or at a concentrated load if the crossing is a jump.

LoadSF shapeBM shape
Point loadVertical jumpKink, still continuous
UDLStraight slopeParabola
No load (between points)HorizontalStraight slope

Standard results

  • Simply supported, UDL w over ℓ: RA = RB = wℓ/2, Mmax = wℓ²/8 at mid-span.
  • Simply supported, point load W at mid-span: RA = RB = W/2, Mmax = Wℓ/4.
  • Cantilever, tip load W: SF at wall = W, BM at wall = −Wℓ.
  • Cantilever, UDL w: SF at wall = wℓ, BM at wall = −wℓ²/2.

Units in these papers

MMD questions mix N, kN, kg and tonnes. Masses such as 61.162 kg are chosen so that × 9.81 gives a round newton load. Where the paper writes kg or t as a load, this studio keeps those as kgf / tonne-force so the printed numbers match. Convert with g = 9.81 when the examiner wants SI.